The scheme of ultra magic square of order 7:
X(1) X(2) X(3) X(4) X(5) X(6) X(7)
X(8) X(9) X(10) X(11) X(12) X(13) X(14)
X(15) X(16) X(17) X(18) X(19) X(20) X(21)
X(22) X(23) X(24) K/2 K-X(24) K-X(23) K-X(22)
K-X(21) K-X(20) K-X(19) K-X(18) K-X(17) K-X(16) K-X(15)
K-X(14) K-X(13) K-X(12) K-X(11) K-X(10) K-X(9) K-X(8)
K-X(7) K-X(6) K-X(5) K-X(4) K-X(3) K-X(2) K-X(1)
There K – associative constant square, S = 7 * K / 2, if S – magic constant square.
The general formula of ultra magic square of order 7:
X(1) = (2*X(18)-2*X(20)- K+2*X(12)+2*X(6)-2*X(14)+2*X(24))/2
X(10) = - X(16)+ X(3)+ X(18)+ X(5)- X(20)- X(21)- K+ X(12)+2*X(6)-2*X(14)+ X(15)+ X(24)
X(11) = -(-2*X(16)+4*X(3)-2*X(20)-2*X(21)+3*K-2*X(23)-4*X(14)-2*X(15)+2*X(24))/2
X(13) = X(16)- X(18)- X(5)+3*K- X(12)-2*X(6)- X(15)
X(17) = -(2*X(3)+2*X(18)-5*K+2*X(6)-2*X(14)+2*X(15)+2*X(24))/2
X(19) = - X(16)+ X(3)- X(20)- X(21)+ K+ X(6)- X(14)+ X(24)
X(2) = -(-2*X(16)+4*X(3)+2*X(18)-2*X(20)- K-2*X(23)+2*X(6)-4*X(14)+2*X(24))/2
X(22) = - X(16)+ X(3)- X(5)+ X(20)+ K- X(23)
X(4) = -(-2*X(3)+2*X(18)+2*X(5)-2*X(21)-7*K+2*X(23)+4*X(12)+4*X(6)+2*X(15))/2
X(7) = - X(16)+ X(18)- X(21)+ X(12)+ X(6)- X(14)+ X(15)
X(8) = - X(3)+ X(5)+ X(23)+ X(14)- X(24)
X(9) = - X(16)+2*X(3)- X(5)+3*K-2*X(23)- X(12)-2*X(14)- X(15)+ X(24)
For a given associative constant square K have 12 free variables and 12 dependent variables.
I am now trying to find a minimal solution with magic constant S = 4487.
The array of primes for this solution:
5 23 53 59 89 101 131 173 179 191 233 251 263 269 311 353 401 419 443 461 509 521 563 599 641 683 719 761 773 821 839 863 881 929 971 1013 1019 1031 1049 1091 1103 1109 1151 1181 1193 1223 1229 1259 1277
I found some solutions with one error, for example:
509 131 1031 1049 1193 401 173
1091 821 839 53 863 761 59
263 599 695* 563 179 929 1259
269 1181 311 641 971 101 1013
23 353 1103 719 587 683 1019
1223 521 419 1229 443 461 191
1109 881 89 233 251 1151 773
K=1282, S=4487